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Jellyfish Compliance with SQIDEP · MCU15/0122
Attached to the e-mail MCU15/0122 - Response to Information Request -Stormwater (Jellyfish compliance) Email 3 of 3.
4
Technical Papers
Table 2. Results of the Shapiro-Wilk Table 3. Results of the Shapiro-Wilk Parametric Test for log-transformed influent
Parametric Test for % removal to test and effluent data.
for normality of the data distribution.
TSS TP TN
%
% TP % TN Influent Effluent Influent Effluent Influent Effluent
TSS
0.039 0.511 0.449 7.012 5.574 2.893 3.215 3.208 2.589
0.040 0.551 0.516 8.054 5.724 3.032 3.234 2.979 2.835
W (test statistic) 0.982 0.928 0.872 W (test statistic) 0.871 0.974 0.954 0.994 0.929 0.913
p-value (>0.05) 0.974 0.441 0.116 p-value (>0.05) 0.111 0.708 0.693 0.996 0.448 0.357
NON-PARAMETRIC TESTING 3. Calculate the mean of the differences CONFIDENCE INTERVAL
If there are no transformations that can ( ) After the data has been proven to be
be utilised to transform the raw data 4. Calculate the standard deviation of the statistically significant, a 95% confidence
into a normal distribution, then non- differences ( ) interval can be constructed. The 95%
parametric tests need to be used to confidence interval is defined in Neyman
test for differences in populations. An 5. Calculate the Standard Error (SE) of the
(1937) as follows:
example is the Wilcoxon Signed-Rank Test mean difference:
instead of the paired t-test (McDonald, “There is a 95% probability that
2014). Confidence intervals can also be the calculated confidence interval
calculated non-parametrically, as described encompasses the true value of the
in Geyer (2003), or utilising methods such population mean.”
6. Calculate the t-statistic, using a
as bootstrapping (Wang, 2001). However, t-distribution with n – 1 degrees of This involves calculating the standard
these methods can sometimes be complex freedom: error, then adding/subtracting the
in nature and require specialised statistical standard error to/from the mean to create
software to conduct statistical modelling. the upper and lower bounds. There is a
A less mathematically intensive method 7. t-distribution tables can be referenced
95% probability that the true population
would be to increase the sample size to to find the corresponding p-value mean exists within these bounds (Tan
larger than 30, as the Central Limit Theorem (probability) with the t-statistic (T) and Tan, 2010; Neyman, 1937).
states that, as sample size increases, the and n – 1 degrees of freedom.
distribution of sample means approaches
a normal distribution, regardless of initial For a 95% confidence level, if the p-value
distribution (Bonacci, 2012). is less than 0.05, the null hypothesis (there where:
is no difference between the sample set
STATISTICAL SIGNIFICANCE – means) is rejected, and the data sets are
PAIRED T-TEST considered statistically different.
The paired t-test is used to assess the
The paired t-test was conducted on the
statistical difference (or significance)
log transform of the influent and effluent
between two normally distributed data
test data, and results are presented in For the 95% confidence level, the Z
sets. In this case, it is used to compare the
Table 4. The paired t-test results for TSS, score equates to 1.96 for a two-tailed test.
influent and effluent data sets to establish
TP and TN are significantly beyond the 95%
if their population means are statistically In this case, as the CRE percentage
confidence level (p<0.05), therefore we can
different. If it can be confirmed that the defines the removal efficiency of the
reject the null hypothesis and conclude that
two sets of data do not have the same stormwater treatment device, confidence
the influent and effluent concentration data
population mean, then it can be concluded intervals were constructed around the
sets are statistically different.
that there is a statistical significance
between them (Cramér, 1946). Table 4. Paired t-test results for the field test data reported in Table 1. The
log-transformed influent and effluent concentrations are being compared for
The following steps describe the statistical difference.
methodology used in conducting a paired
H0 = there is no difference between the
t-test (Shier, 2004):
concentration means of the influent & TSS TP TN
1. Construct a null hypothesis, i.e. effluent populations
that there is no statistical difference
Mean of Differences (µd) Loge(mg/L) 2.267 1.011 0.672
between the population means.
Std. dev. of Differences(σd) 0.858 0.746 0.525
2. Calculate the difference for each pair.
This is done by subtracting the effluent Std Error (SE) 0.271 0.746 0.166
concentration from the influent
T-Statistic 8.357 4.288 4.042
concentration for each event (i.e.
for each Degrees of Freedom (n-1) 9 9 9
event pair of data, where i varies from
Paired t-test Result (Must be < 0.05) 1.6x10 -5
0.002 0.0029
1 to n).
WATER MAY 2015
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